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-16x^2+50x+75=0
a = -16; b = 50; c = +75;
Δ = b2-4ac
Δ = 502-4·(-16)·75
Δ = 7300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7300}=\sqrt{100*73}=\sqrt{100}*\sqrt{73}=10\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{73}}{2*-16}=\frac{-50-10\sqrt{73}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{73}}{2*-16}=\frac{-50+10\sqrt{73}}{-32} $
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